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| | GaussianGuess (const coordT &origin, const double alpha, const std::vector< int > ijk=std::vector< int >(NDIM)) |
| | ctor
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| | GaussianGuess (const coordT &origin, const double alpha, const std::vector< int > ijk=std::vector< int >(NDIM)) |
| | ctor
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| | GaussianGuess (const coordT &origin, const double alpha, int l) |
| | ctor
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| double | operator() (const coordT &xyz) const |
| | You should implement this to return f(x)
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| T | operator() (const coordT &xyz) const |
| | virtual function cannot be SFINAE'ed
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| template<class R = T> |
| std::enable_if< std::is_same< R, std::complex< double > >::value, R >::type | val (const coordT &xyz) const |
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| template<class R = T> |
| std::enable_if< std::is_same< R, double >::value, R >::type | val (const coordT &xyz) const |
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| | FunctionFunctorInterface () |
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| virtual | ~FunctionFunctorInterface () |
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| virtual coeffT | coeff (const keyT &) const |
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| virtual void | operator() (const Vector< double *, 1 > &xvals, double *fvals, int npts) const |
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| virtual void | operator() (const Vector< double *, 2 > &xvals, double *fvals, int npts) const |
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| virtual void | operator() (const Vector< double *, 3 > &xvals, double *fvals, int npts) const |
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| virtual void | operator() (const Vector< double *, 4 > &xvals, double *fvals, int npts) const |
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| virtual void | operator() (const Vector< double *, 5 > &xvals, double *fvals, int npts) const |
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| virtual void | operator() (const Vector< double *, 6 > &xvals, double *fvals, int npts) const |
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| virtual bool | provides_coeff () const |
| | does this functor directly provide sum coefficients? or only function values?
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| virtual bool | screened (const Vector< double, NDIM > &c1, const Vector< double, NDIM > &c2) const |
| | Can we screen this function based on the bounding box information?
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| void | set_length_scale (double lo) |
| | adapt the special level to resolve the smallest length scale
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| virtual Level | special_level () const |
| | Override this to change the minimum level of refinement at special points (default is 6)
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| virtual std::vector< Vector< double, NDIM > > | special_points () const |
| | Override this to return list of special points to be refined more deeply.
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| virtual bool | supports_vectorized () const |
| | Does the interface support a vectorized operator()?
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| virtual coeffT | values (const keyT &key, const Tensor< double > &tensor) const |
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| | FunctionFunctorInterface () |
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| virtual | ~FunctionFunctorInterface () |
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| virtual coeffT | coeff (const keyT &) const |
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| virtual void | operator() (const Vector< double *, 1 > &xvals, T *fvals, int npts) const |
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| virtual void | operator() (const Vector< double *, 2 > &xvals, T *fvals, int npts) const |
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| virtual void | operator() (const Vector< double *, 3 > &xvals, T *fvals, int npts) const |
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| virtual void | operator() (const Vector< double *, 4 > &xvals, T *fvals, int npts) const |
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| virtual void | operator() (const Vector< double *, 5 > &xvals, T *fvals, int npts) const |
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| virtual void | operator() (const Vector< double *, 6 > &xvals, T *fvals, int npts) const |
| |
| virtual bool | provides_coeff () const |
| | does this functor directly provide sum coefficients? or only function values?
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| virtual bool | screened (const Vector< double, NDIM > &c1, const Vector< double, NDIM > &c2) const |
| | Can we screen this function based on the bounding box information?
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| void | set_length_scale (double lo) |
| | adapt the special level to resolve the smallest length scale
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| virtual Level | special_level () const |
| | Override this to change the minimum level of refinement at special points (default is 6)
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| virtual std::vector< Vector< double, NDIM > > | special_points () const |
| | Override this to return list of special points to be refined more deeply.
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| virtual bool | supports_vectorized () const |
| | Does the interface support a vectorized operator()?
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| virtual coeffT | values (const keyT &key, const Tensor< double > &tensor) const |
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template<std::size_t NDIM>
class GaussianGuess< NDIM >
an N-dimensional real-valued Gaussian function
the function looks like [ f(r) = x^i y^j .. z^k exp(-alpha r^2) ]